7.5.5 Contains A Vowel CodeHS Answers
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7.5.5 Contains a Vowel CodeHS Answers
Quizzma Team
The most common answer is:
use in to determine if word contains any vowels!
word = “dodo”
def contains_vowel(word):
vowels = [“u”, “o”, “i”, “a”, “e”]
for i in vowels:
for letter in word:
if letter == i:
return True
else:
return False
print (contains_vowel(word))
To streamline the function and accurately check if the word contains any vowel, you can utilize the in operator
moreeffectively. The current nested loops approach isn’t optimal because the function will return False after checking
only the first letter against the first vowel, which isn’t the intended logic.
Here’s how you can revise thecode:
word = "dodo"
def contains_vowel(word):
vowels = ["u", "o", "i", "a", "e"]
for letter in word:
if letter in vowels:
return True
return False
print(contains_vowel(word))
Thiscodedefines a function contains_vowel that iterates over each letter in word andchecksif it is in the list of vowels.
If any letter in the word is a vowel, it immediately returns True . If the loop completes without finding a vowel, the
function returns False after the loop, ensuring that the entire word is checked.
This corrected approach ensures that the function correctly identifies whether any vowel is present in the input word
“dodo”, and it will print True because “o” is a vowel found in “dodo”.
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4/7/26, 5:56 PM
7.5.5 Contains a Vowel CodeHS Answers » Quizzma
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