7.5.5 Contains A Vowel CodeHS Answers

7.5.5 Contains A Vowel CodeHS Answers

7.5.5 Contains A Vowel CodeHS Answers

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7.5.5 Contains a Vowel CodeHS Answers
Quizzma Team
The most common answer is:
use in to determine if word contains any vowels!
word = “dodo”
def contains_vowel(word):
vowels = [“u”, “o”, “i”, “a”, “e”]
for i in vowels:
for letter in word:
if letter == i:
return True
else:
return False
print (contains_vowel(word))
To streamline the function and accurately check if the word contains any vowel, you can utilize the in operator
moreeffectively. The current nested loops approach isn’t optimal because the function will return False after checking
only the first letter against the first vowel, which isn’t the intended logic.
Here’s how you can revise thecode:
word = "dodo"
def contains_vowel(word):
vowels = ["u", "o", "i", "a", "e"]
for letter in word:
if letter in vowels:
return True
return False
print(contains_vowel(word))
Thiscodedefines a function contains_vowel that iterates over each letter in word andchecksif it is in the list of vowels.
If any letter in the word is a vowel, it immediately returns True . If the loop completes without finding a vowel, the
function returns False after the loop, ensuring that the entire word is checked.
This corrected approach ensures that the function correctly identifies whether any vowel is present in the input word
“dodo”, and it will print True because “o” is a vowel found in “dodo”.
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7.5.5 Contains a Vowel CodeHS Answers » Quizzma
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