
Select a point value to view scoring criteria, solutions, and/or examples and to score the response. The answer to part (b)
must be consistent with part (a). If a student makes an error in a previous part of the question, the student can still earn
credit in a later part if the incorrect answer is used correctly.
0 1
The response indicates that the process is not thermodynamically favorable at
because is positive.(OR, if
part (a) indicates a negative value of
,the response indicates that the process is thermodynamically favorable
because
is negative.)
Part (c)
Select a point value to view scoring criteria, solutions, and/or examples and to score the response.
0 1
The response indicates that even though the process is not thermodynamically favorable, it does not follow that the
process does not occur at all. At equilibrium, the reactant (liquid water) is
favored over the product (water vapor). This
does not mean that some of the liquid water cannot evaporate to become water vapor.
Part (d)
Select a point value to view scoring criteria, solutions, and/or examples and to score the response.
0 1
The response indicates that the change in entropy between ice,
, and water vapor, , is greater because the
entropy of water in the solid phase, with molecules bound in fixed positions within the solid, is less than the entropy of
water in the liquid phase, with molecules able to move more freely and form a greater number of spatial configurations.
Water in the gas phase, with molecules much more dispersed and even more free to move, has the highest entropy of the
three phases. Therefore, process 1 (sublimation) involves a greater change in entropy than process 2 (vaporization of a
liquid) does.
Scoring Guide
Unit 9 Progress Check: FRQ
Page 2 of 7
AP Chemistry