Solutions to Chapter 10 Electrochemical Cells Practice Problems

Solutions to Chapter 10 Electrochemical Cells Practice Problems

Electrochemical cells are fundamental in understanding redox reactions, and this resource provides detailed solutions to practice problems from Chapter 10. It covers galvanic cells involving zinc, magnesium, silver, and nickel, explaining the concepts of oxidation and reduction at each electrode. Students will find step-by-step guidance on identifying anodes and cathodes, drawing cell diagrams, and writing balanced ionic equations. Ideal for chemistry students preparing for exams or anyone seeking a deeper understanding of electrochemistry.

Key Points

  • Explains the identification of anodes and cathodes in galvanic cells.
  • Covers oxidation and reduction processes for zinc and magnesium.
  • Includes diagrams illustrating electron flow in electrochemical cells.
  • Provides balanced ionic equations for reactions involving nickel and silver.
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Unit 5 Part B ● MHR 65
Solutions to Practice Problems in
Chapter 10 Electrochemical Cells
Using Half-Reactions to Sketch a Galvanic Cell
(Student textbook page 641)
1. In a galvanic cell involving zinc and magnesium, which electrode will be the anode and
which will be the cathode?
What Is Required?
You are asked to identify the anode and cathode of a galvanic cell.
What Is Given?
You are given that one electrode is zinc and the second electrode is magnesium. You are also
given Relative Strengths of Oxidizing and Reducing Agents, Table 9.2 on page 587 of the
student textbook.
Plan Your Strategy
Act on Your Strategy
Identify the stronger reducing agent from
Table 9.2.
Between zinc and magnesium, magnesium is
the stronger reducing agent.
Since the stronger reducing agent is
always oxidized, and oxidation occurs at
the anode, the anode can be identified.
Since magnesium is the stronger reducing
agent, magnesium is oxidized and thus is the
anode in the galvanic cell.
Once the anode is identified, the other
electrode will be the cathode.
Given that the magnesium electrode is the
anode, the zinc electrode must be the cathode.
Check Your Solution
The stronger reducing agent, according to Table 9.2, is the anode, and the weaker reducing
agent is the cathode. The solution is correct.
66 MHR ● Chemistry 12 Solutions Manual 978-0-07-106042-4
2. Explain where the oxidation and the reduction are occurring in a galvanic cell involving zinc
and magnesium.
What Is Required?
You are to identify where the oxidation and the reduction are occurring in a galvanic cell.
What Is Given?
You are given that one electrode is zinc and the second electrode is magnesium. You are also
given Relative Strengths of Oxidizing and Reducing Agents, Table 9.2 on page 587 of the
student textbook.
Plan Your Strategy
Act on Your Strategy
Identify the stronger reducing agent from
Table 9.2.
Between zinc and magnesium, magnesium
is the stronger reducing agent.
Since the stronger reducing agent is always
oxidized, oxidation occurs at the anode.
Oxidation occurs at the magnesium
electrode.
The weaker reducing agent is always reduced
and reduction occurs at the cathode.
Reduction occurs at the zinc electrode.
Check Your Solution
Oxidation occurs at the electrode that is the stronger reducing agent, and reduction occurs at
the electrode that is the weaker reducing agent. The solution is correct.
Unit 5 Part B ● MHR 67
3. Draw a diagram of a galvanic cell involving zinc and magnesium, and indicate the direction
of electron flow.
What Is Required?
You are to draw a galvanic cell, labelling the anode, the cathode, and the direction of electron
flow.
What Is Given?
You are given the electrodes of magnesium and zinc for this galvanic cell.
Plan Your Strategy
Act on Your Strategy
Identify the pieces of the galvanic
cell.
The magnesium is the anodethe site of oxidation,
where magnesium ions flow into solution and
electrons leave the electrode and flow through the
voltmeter as they move to the zinc cathode. The zinc
is the cathode
the site of reduction, where zinc ions
flow onto the electrode as they pick up electrons.
Identify the direction of electron
flow.
In a galvanic cell, electrons flow from the anode to
the cathode, in t
his case, from the magnesium
electrode to the zinc electrode.
Identify the ion flow in the half-
cells.
Ions of magnesium will flow into the oxidation half-
reaction as the atoms of magnesium lose electrons.
Ions of zinc will flow onto the zinc electrode as
they
pick up electrons during the reduction.
Identify the ion flow in the salt
bridge.
Negative ions in the salt bridge will migrate towards
the oxidation half
-
reaction and positive charge builds
up in the cell. Positive ions will migrate towards the
red
uction half-cell as positive charge is removed
from the half
-
cell, leaving a net negative charge in
this half
-
cell that will attract the positive ions in the
salt bridge.
Sketch the apparatus, including the
beakers, electrodes, conducting
wires, voltmeter, salt bridge, and
electron flow.
Check Your Solution
Electrons flow from the site of oxidation at the magnesium anode to the site of reduction at
the zinc cathode. The drawing is correct.
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End of Document
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FAQs of Solutions to Chapter 10 Electrochemical Cells Practice Problems

What is the role of the anode in a galvanic cell?
The anode in a galvanic cell is the electrode where oxidation occurs. This is where electrons are lost by the reducing agent, which in turn causes positive ions to flow into the solution. For example, in a galvanic cell involving magnesium, magnesium acts as the anode, losing electrons and forming magnesium ions. This process is crucial for the overall functioning of the cell, as it drives the flow of electrons towards the cathode.
How do you determine the direction of electron flow in a galvanic cell?
The direction of electron flow in a galvanic cell is from the anode to the cathode. This is because electrons are produced at the anode during the oxidation process and are then attracted to the cathode, where reduction occurs. For instance, in a cell with zinc and magnesium, electrons flow from the magnesium anode to the zinc cathode. Understanding this flow is essential for analyzing the operation of electrochemical cells.
What are the half-reactions involved in the zinc and magnesium galvanic cell?
In a galvanic cell involving zinc and magnesium, the oxidation half-reaction for magnesium is represented as Mg(s) → Mg2+(aq) + 2e–. This indicates that solid magnesium loses two electrons to form magnesium ions. The reduction half-reaction for zinc is Zn2+(aq) + 2e– → Zn(s), showing that zinc ions gain two electrons to become solid zinc. These half-reactions are critical for balancing the overall redox reaction in the cell.
What is the significance of the salt bridge in a galvanic cell?
The salt bridge in a galvanic cell serves to maintain electrical neutrality by allowing the flow of ions between the two half-cells. It prevents the buildup of charge that would otherwise stop the reaction. As oxidation occurs at the anode, positive ions enter the solution, and the salt bridge allows negative ions to migrate toward the anode to balance this charge. This ionic movement is essential for the continuous operation of the galvanic cell.
How do you balance the ionic equation for a galvanic cell reaction?
To balance the ionic equation for a galvanic cell reaction, start by writing the oxidation and reduction half-reactions separately. For example, in the reaction between nickel and silver, the oxidation half-reaction is Ni(s) → Ni2+(aq) + 2e–, while the reduction half-reaction is 2Ag+(aq) + 2e– → 2Ag(s). Ensure that the number of electrons lost in oxidation equals the number gained in reduction. Finally, combine the half-reactions, canceling out the electrons to yield the balanced overall equation.
What factors determine which metal is the anode in a galvanic cell?
The anode in a galvanic cell is determined by the relative strengths of the metals as reducing agents. The metal that is the stronger reducing agent will be oxidized and thus serve as the anode. For instance, in a comparison between nickel and silver, nickel is the stronger reducing agent and will act as the anode, while silver, being the weaker reducing agent, will be the cathode. This relationship is essential for predicting the behavior of different metal combinations in electrochemical cells.
What concepts are essential for understanding electrochemical cells?
Key concepts essential for understanding electrochemical cells include oxidation and reduction reactions, the roles of anodes and cathodes, and the flow of electrons and ions. Additionally, knowledge of half-reactions, balanced ionic equations, and the function of the salt bridge is crucial. These concepts help in analyzing how galvanic cells operate and the principles behind energy conversion in electrochemical systems.

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